C Program to Store Information using Structures with Dynamic Memory Allocation

C program to store information using structures with dynamic memory allocation.

In this article, you will learn how to write a C program to store the student's information using the C structure and Dynamic Memory Allocation. We will use the C pointers & malloc() function to implement this program.

Example

You should know about the following topics in C programming to understand this program:

• C Structure
• C Pointers
• Dynamic Memory Allocation in C

Source

// C Program to Store Information using Structures with Dynamic Memory Allocation
#include <stdio.h>
#include <stdlib.h>

// Make the structure of the student records
struct students {
    char name[25];
    char email[25];
    int class;
};

// It's the main function of the program
int main() {
    struct students *pointer;
    int records_count;

    // Step-1 INPUT the no. of records
    printf("Enter the record count: ");
    scanf("%d", &records_count);

    // Step-2 Allocate the memories to the counted records by using the `malloc` function
    pointer = (struct students *)malloc(records_count * sizeof(struct students));

    // Step-3 Iterate over the counted records to take the inputs from the user
    for (int i = 0; i < records_count; i++) {
        printf("\nEnter the student's information(Name, Email, and Class):\n");
        scanf("%s %s %d", (pointer + i)->name, (pointer + i)->email, &(pointer + i)->class);
    }

    // Step-4 Final output of the program to display the student records
    printf("\nStudent's Information:\n");
    printf("-----------------------------------------------------\n");
    for (int i = 0; i < records_count; i++) {
        printf("%s\t%s\t%d\n", (pointer + i)->name, (pointer + i)->email, (pointer + i)->class);
        printf("-----------------------------------------------------\n");
    }

    return 0;
}

Run

Output