Spiral Pattern in Python language

Spiral pattern in python language. In this program, you will learn how to print the spiral pattern in python language.

Source Code

# Spiral Pattern in Python language

def spiralPrint(m, n, arru):
    # m is the rows
    # n is the columns
    # arru is the list of elements
    k, l = 0, 0

    while k < m and l < n:
        pass
        # This will print the first row from the remaining rows
        for i in range (l, n):
            print (arru[k][i], end=", ")

        k += 1

        # This will print the last column from the remaining columns
        for i in range (k, m):
            print (arru[i][n - 1], end=", ")

        n -= 1

        # This will print the last row from the remaining rows
        if k < m:
            for i in range (n - 1, l - 1, -1):
                print (arru[m - 1][i], end=", ")

            m -= 1

        # This will print the first column from the remaining columns
        if l < n:
            for i in range (m - 1, k - 1, -1):
                print (arru[i][l], end=", ")

            l += 1

    print (end="\n")

arru = [
    [31, 32, 33, 34, 35, 36],
    [47, 48, 49, 40, 41, 42],
    [53, 54, 55, 56, 57, 58]
]

print ("-----The spiral pattern is-----")
# This will print the spiral pattern
spiralPrint(3, 6, arru)

Run Program

Output