Example: Reverse Integer in Java

// Reverse Integer
import java.util.Scanner;

// Main class containing the entry point of the program
public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter an integer to reverse: ");
        int x = scanner.nextInt();
        scanner.close();

        int reversedNum = reverse(x);
        System.out.println("Reversed number: " + reversedNum);
    }

    public static int reverse(int x) {
        long reversed = 0; // Use long to detect potential overflow before casting to int

        while (x != 0) {
            int digit = x % 10; // Get the last digit
            reversed = reversed * 10 + digit; // Append the digit to the reversed number
            x /= 10; // Remove the last digit from the original number

            // Check for overflow before the next iteration
            // If reversed goes beyond Integer.MAX_VALUE or Integer.MIN_VALUE, it's an overflow
            if (reversed > Integer.MAX_VALUE || reversed < Integer.MIN_VALUE) {
                return 0; // Return 0 as per LeetCode's common requirement for overflow
            }
        }
        return (int) reversed; // Cast back to int for the final result
    }
}