Example: Array Element Frequency using Nested Loops in Java

// Array Element Frequency using Nested Loops
import java.util.Scanner;

// Main class containing the entry point of the program
public class Main {
    public static void main(String[] args) {
        // Step 1: Initialize the array
        int[] arr = {10, 20, 20, 10, 10, 30, 40, 50, 20, 40};
        int n = arr.length;

        // Step 2: Create a boolean array to keep track of visited elements
        // This helps avoid recounting elements that have already been processed.
        boolean[] visited = new boolean[n];

        // Step 3: Iterate through the array
        for (int i = 0; i < n; i++) {
            // Step 3a: Skip if the element at index 'i' has already been visited
            if (visited[i]) {
                continue;
            }

            // Step 3b: Initialize count for the current element
            int count = 1;

            // Step 3c: Iterate through the rest of the array (elements after 'i')
            // to find duplicates of arr[i]
            for (int j = i + 1; j < n; j++) {
                if (arr[i] == arr[j]) {
                    count++;
                    visited[j] = true; // Mark duplicate as visited to avoid recounting
                }
            }

            // Step 3d: Print the frequency of the current unique element
            System.out.println(arr[i] + ": " + count + " times");
        }
    }
}