Minimum Sum Of Absolute Difference Of Pairs Of Two Arrays In C
Minimizing the sum of absolute differences between elements of two arrays is a common optimization problem with applications in various fields. The goal is to pair elements from two arrays such that the total sum of the absolute differences between each pair is as small as possible. In this article, you will learn an efficient approach to solve this problem in C, focusing on the core concept of sorting.
Problem Statement
Given two arrays, A and B, each containing N integer elements, the objective is to find a permutation of array B (or A) such that the sum of the absolute differences |A[i] - B[i]| for all i from 0 to N-1 is minimized. This problem requires an optimal pairing strategy to achieve the smallest possible total difference.
For instance, if A = {4, 1} and B = {2, 3}, we need to find pairings that minimize |A[i] - B[i]|.
Possible pairings:
- (4,2), (1,3):
|4-2| + |1-3| = 2 + 2 = 4 - (4,3), (1,2):
|4-3| + |1-2| = 1 + 1 = 2
Example
Consider two arrays:
- Array
A:{4, 1, 8, 7} - Array
B:{2, 3, 6, 5}
The minimum sum of absolute differences for these arrays, achieved by sorting them first and then summing the absolute differences of corresponding elements, would be 6.
Background & Knowledge Prerequisites
To understand and implement the solution for this problem, readers should have a basic grasp of:
- C Language Fundamentals: Variables, arrays, loops, and functions.
- Standard Library Functions: Specifically
qsortfromstdlib.hfor sorting arrays andabsfrommath.h(orstdlib.hfor integers). - Pointers: A basic understanding of how pointers work in C, especially when using
qsort. - Sorting Algorithms Concept: An intuitive understanding that sorting helps organize data for efficient processing.
Use Cases or Case Studies
This problem, or variations of it, arises in several practical scenarios:
- Resource Allocation: Matching tasks with available resources where each task has a specific requirement and each resource has a specific capability, aiming to minimize the "mismatch" cost.
- Data Matching: In data analysis, pairing similar data points from two different datasets to minimize discrepancies, for example, matching two sensor readings taken at slightly different times.
- Production Planning: Assigning workers to machines, where each worker has a skill level and each machine has a complexity level, to minimize the total effort difference.
- Supply Chain Optimization: Pairing demand points with supply sources to minimize transportation costs based on location differences.
- Image Processing: In image comparison or restoration, minimizing the sum of absolute differences between pixel values of two images to quantify similarity or error.
Solution Approaches
The most efficient and standard approach to minimize the sum of absolute differences between paired elements of two arrays is to sort both arrays.
Sorting Both Arrays
The mathematical intuition behind this approach is that to minimize the sum sum(|A[i] - B[i]|), you should pair elements that are "close" to each other in value. This is best achieved by sorting both arrays. If both arrays are sorted, pairing A[i] with B[i] for all i ensures that smaller elements are paired with smaller elements and larger elements with larger elements, effectively minimizing the individual absolute differences, and consequently, their sum.
// Minimum Sum of Absolute Difference of Pairs
#include <stdio.h> // For printf
#include <stdlib.h> // For qsort, abs
#include <math.h> // For fabs (though abs is sufficient for integers)
// Comparison function for qsort
int compareIntegers(const void *a, const void *b) {
return (*(int*)a - *(int*)b);
}
int main() {
// Step 1: Define two arrays of equal size
int arrayA[] = {4, 1, 8, 7};
int arrayB[] = {2, 3, 6, 5};
int n = sizeof(arrayA) / sizeof(arrayA[0]); // Calculate the size of the arrays
printf("Original Array A: ");
for (int i = 0; i < n; i++) {
printf("%d ", arrayA[i]);
}
printf("\\n");
printf("Original Array B: ");
for (int i = 0; i < n; i++) {
printf("%d ", arrayB[i]);
}
printf("\\n\\n");
// Step 2: Sort both arrays using qsort
// qsort(base, num_elements, size_of_each_element, comparison_function)
qsort(arrayA, n, sizeof(int), compareIntegers);
qsort(arrayB, n, sizeof(int), compareIntegers);
printf("Sorted Array A: ");
for (int i = 0; i < n; i++) {
printf("%d ", arrayA[i]);
}
printf("\\n");
printf("Sorted Array B: ");
for (int i = 0; i < n; i++) {
printf("%d ", arrayB[i]);
}
printf("\\n\\n");
// Step 3: Calculate the minimum sum of absolute differences
long long min_abs_diff_sum = 0; // Use long long for sum to prevent overflow
for (int i = 0; i < n; i++) {
min_abs_diff_sum += abs(arrayA[i] - arrayB[i]);
}
// Step 4: Print the result
printf("Minimum sum of absolute differences: %lld\\n", min_abs_diff_sum);
return 0;
}
Sample Output
Original Array A: 4 1 8 7
Original Array B: 2 3 6 5
Sorted Array A: 1 4 7 8
Sorted Array B: 2 3 5 6
Minimum sum of absolute differences: 6
Stepwise Explanation
- Include Headers: The program starts by including necessary headers:
stdio.hfor input/output,stdlib.hforqsortandabs, andmath.h(thoughabsfromstdlib.his sufficient for integers,fabsis for doubles). - Comparison Function: A custom comparison function
compareIntegersis defined. This is required byqsortto know how to order elements. It takes twoconst voidpointers, casts them toint, dereferences them, and returns their difference. - Array Initialization: Two integer arrays,
arrayAandarrayB, are initialized with example values. The sizenis calculated dynamically. - Display Original Arrays: The program prints the content of the original arrays for reference.
- Sorting Arrays: Both
arrayAandarrayBare sorted in ascending order usingqsort.qsortis a generic sorting function that requires the base address of the array, the number of elements, the size of each element, and a pointer to a comparison function. - Display Sorted Arrays: The program then prints the content of the sorted arrays to show the effect of
qsort. - Calculate Minimum Sum: A
long longvariableminabsdiffsumis initialized to 0. A loop iterates fromi = 0ton-1, calculating the absolute difference betweenarrayA[i]andarrayB[i]usingabs()and adding it tominabsdiffsum. Usinglong longfor the sum is a good practice to prevent potential integer overflow if the differences and array sizes are large. - Print Result: Finally, the calculated
minabsdiff_sumis printed to the console.
Conclusion
The problem of finding the minimum sum of absolute differences of pairs between two arrays is efficiently solved by simply sorting both arrays. This intuitive approach leverages the property that pairing elements of similar magnitude minimizes their absolute difference, and when applied across all pairs after sorting, results in the globally minimal sum. This method is straightforward to implement and computationally efficient, making it a preferred solution for this type of optimization.
Summary
- To minimize the sum of absolute differences between paired elements of two arrays, sort both arrays independently.
- After sorting, iterate through the arrays and sum the absolute differences of elements at corresponding indices.
- This approach ensures that elements of similar values are paired, leading to the smallest possible total sum of differences.
- The C standard library function
qsort()is ideal for sorting the arrays efficiently.